When $ a \ne 0 $, there are two solutions to $ax^2 + bx + c = 0$ and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
$$\begin{bmatrix} 1 & 2 & 3\\ a & b & c \end{bmatrix} $$
- lista 1
- lista 2
- let $D=0$
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